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4m^2+100m=0
a = 4; b = 100; c = 0;
Δ = b2-4ac
Δ = 1002-4·4·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-100}{2*4}=\frac{-200}{8} =-25 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+100}{2*4}=\frac{0}{8} =0 $
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